Talk:Galois theory

The following is just a scratch to work out the 1st non-stub version of the article

Galois theory is an area of mathematical study that originated with Evariste Galois around 1830, as part of an effort to understand the relationships between the roots of polynomials, in particular why there are no simple formulas for extracting the roots of the general polynomial of fifth (or higher) degree.

Introduction

Galois expressed his theory in terms of polynomials and complex numbers, today Galois theory is usually formulated using general field theory.

Key concepts are field extensions and groups, which should be thoroughly understood before Galois theory can be properly studied.

The core idea behind Galois theory is that given a polynomial $\alpha$ with coefficients in a field K (typically the rational numbers), there exists

• a field L that contains K (or a field isomorphic to K) as a subfield, and also the roots of $\alpha$.
• a group containing all automorphisms in L that leave the elements in K untouched.

Providing certain technicalities are fullfilled, the structure of this group contains information about the nature of the roots, and whether the equation $\alpha =0$ has solutions expressible as radical expressions - i.e. formulas involving a simple sequence of ordinary arithmetical expressions and rational powers.

Basic concepts/glossary

• Polynomial over a field K: An expression of the form $a_{n-1}x^{n-1}+...+a_{1}x^{1}+a_{0}$, with $a_{0},a_{1},...a_{n-1}\in K$.
• Root of a polynomial $\alpha$: a number r such that $\alpha (r)=0$
• A splitting field for a polynomial $\alpha$: A field which contains the original field K as a subfield, and also contains all the roots of $\alpha$.

Summary of the theory

Given a polynomial $\alpha$ with coefficients in some field K, it may be the case that the equation $\alpha =0$ has no solutions in K. In that case, $\alpha$ is said to be irreducible in K.

Anyway, if K is a subfield of C, we are guaranteed by the fundamental theorem of algebra that there exists a subfield of C containing K and all the roots.

...blabber about field of characteristic <> 0 ...

Field extensions

Any field K can be "extended" by including one or more "foreign" elements, f.i. the field Q can be extended by including sqr(2). The resulting field is the subset of R described by a+b sqrt(2), a,b in Q.

Similarly, if r1, r2, ... rn are roots of a polynomial α , a lattice of extension fields may be constructed. ...

Algebraic extension vs transcendental...

The order of an extension ...

Normal extensions and splitting fields ...

Given a polynomial $\alpha$ with coefficients in a field K, there exists a field M ⊇ K - known as a splitting field of $\alpha$ - which contains all the roots of $\alpha$.

The Galois correspondence

The correspondence between the Galois group subgroup structure and the field extension lattice ...

Caveat - separability - only relevant with non-zero characteristic fields.

Soluble groups ... Why neither the quintic nor its friend S5 are "soluble". Why 60 degree angles won't let themselves be "trisected". Why this was a triumph for Galois theory, 2000+ year old riddles solved.

How much to rely on an extra "Field extensions" article?

Ragnar Schroder 05:38, 12 December 2007 (CST)